V=H+5t^2/2

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Solution for V=H+5t^2/2 equation:



=+5V^2/2
We move all terms to the left:
-(+5V^2/2)=0
We get rid of parentheses
-5V^2/2=0
We multiply all the terms by the denominator
-5V^2=0
a = -5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-5)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$V=\frac{-b}{2a}=\frac{0}{-10}=0$

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